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Appendix
Proof of Lemma 1. Let µ > 0 be arbitrary and define an auxiliary function Φ(x) =
kxk. Similar to Lemma 11 in [18] this function will serve the basis to construct function
W which satisfies inequality (15). Taking derivative of Φ along the solutions of (10) we
obtain
∂Φ
∂x
(x) f(x, u) ≤ kf(x, u)k . (31)
Notice that function f satisfies the assumptions of Lemma 2 and therefore there exist
C
1
functions λ
i
, C
1
functions κ ∈ K and positive constants c
i
> 0, i = 1, 2 such that
λ
i
(s) = (κ
i
(s) + c
i
) s, (32)
and
kf(x, u)k ≤ λ
1
(kxk) + λ
2
(kuk). (33)