So (N,w) is selection superadditive by Proposition
3.6. Its length game, however, is not superadditive,
since for any two nonempty coalitions with the empty
intersection |w|(S) + |w|(T ) = 2 6≤ 1 = |w|(S ∪ T )
holds.
In (ii), we can construct the following counterex-
ample (N, w
0
). Set w
0
(S) = [0,|S|] for any nonempty
S. The lower border game is trivially superaddi-
tive. For the upper game, w
0
(S) +w
0
(T ) = |S| +|T | =
|S ∪ T | = w
0
(S ∪ T ) for any S,T with the empty inter-
section, so the upper game is superadditive. Observe
that the length game is the same as the upper border
game. This shows interval superadditivity.
However, (N,w
0
) is clearly not selection superad-
ditive because of nonzero upper bounds, zero lower
bounds of nonempty coalitions and the characteriza-
tion of SeSIG
N
taken into account.
(iii) Nonempty intersection can be argumented
easily by taking some superadditive game (N, c) ∈
G
N
. Then we can define corresponding game (N,d) ∈
IG
N
with
d(S) = [c(S),c(S)], ∀S ∈ 2
N
.
Game (N,d) is selection superadditive since its only
selection is (N,c). And it is superadditive inter-
val game since border games are supermodular and
length game is |w|(S) = 0 for every coalition, which
trivially implies its superadditivity.
Proposition 3.9. For every player set N with |N| > 1,
following assertions hold.
(i) SeCIG
N
6⊆ CIG
N
.
(ii) CIG
N
6⊆ SeCIG
N
.
(iii) SeCIG
N
∩ CIG
N
6=
/
0.
Proof. For (i), take a game (N, w) assigning to each
nonempty coalition S interval [2
|S|
−2, 2
|S|
−1]. From
Proposition 3.7, we get that for inequalities which
must hold in order to meet necessary conditions of
game to be selection convex, |S| < |S ∪ T | and |T | <
|S ∪T | must hold. That gives the following inequality.
w(S) + w(T ) ≤ (2
|S∪T |−1
− 1) + (2
|S∪T |−1
− 1)
= 2
|S∪T |
− 2
= w(S ∪ T )
≤ w(S ∪ T ) + w(S ∩ T )
This concludes that (N, w) is selection convex. We see
that the border games and the length game are convex
too. To have a game so that it is selection convex
and not convex interval game, we can take (N, c) and
set c(S) := w(S) for S 6= N and v(N) := [w
(S),w(S)].
Now the game (N,c) is still selection convex, but its
length game is not convex, so (N,v) is not convex in-
terval game, which is what we wanted.
In (ii), we can take a game (N, w
0
) from the proof
of Proposition 3.8(ii). From the fact that |S| + |T | =
|S∪T |+|S∩T |, it is clear that w
0
is convex. The lower
border game is trivially convex and the length game is
the same as upper. However, for nonempty S,T ∈ 2
N
such that S 6⊆ T , T 6⊆ S, S 6=
/
0, T 6=
/
0, convex selection
games characterization is clearly violated.
As for (iii), we can use the same steps as in (iii) of
Proposition 3.8 or we can use a game (N,w) from (i)
of this theorem.
4 CORE COINCIDENCE
In G
¨
ok’s PhD thesis (Alparslan-G
¨
ok, 2009), the fol-
lowing topic is suggested: “A difficult topic might be
to analyze under which conditions the set of payoff
vectors generated by the interval core of a coopera-
tive interval game coincides with the core of the game
in terms of selections of the interval game.”
We decided to examine this topic. We call it a
core coincidence problem. This subsection shows our
results.
Note 4.1. We remind the reader that whenever we
talk about relation and maximum, minimum, maxi-
mal, minimal vectors, we mean relation ≤ on real
vectors unless we say otherwise.
The main thing to notice is that while the interval
core gives us a set of interval vectors, selection core
gives us a set of real numbered vectors. To be able to
compare them, we need to assign to a set of interval
vectors a set of real vectors generated by these interval
vectors. That is exactly what the following function
gen does.
Definition 4.2. The function gen : 2
IR
N
→ 2
R
N
maps
to every set of interval vectors a set of real vectors. It
is defined as
gen(S) =
[
s∈S
(x
1
,x
2
,.. .,x
n
) | x
i
∈ s
i
, s ∈ IR
N
.
Core coincidence problem can be formulated as
this: What are the necessary and sufficient condition
to satisfy gen(C (w)) = S C (w)?
The main results of this subsection are the two fol-
lowing theorems which give an answer to the afore-
mentioned question.
Note 4.3. In the following text, by mixed system we
mean a system of equalities and inequalities.
Proposition 4.4. For every interval game (M,w) we
have gen(C (w)) ⊆ S C (w).
Proof. For any x
0
∈ gen(C (w)), inequality v(N) ≤
∑
i∈N
x
0
i
≤ v(N) obviously holds. Furthermore, x
0
is in
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