According to the coupling transformers principle, to
a have resonant circuit, the product of inductance and
capacitance in the circuits must be equal (T.
Mohamadi, 2011).
...
rp rs rt p p s s t t
ff LCLCLC
=
==⎯⎯→==
(2)
To solve and analyze the circuit, the KVL law is
applied to the Thevenin equivalent circuit of figure
2.
1
()
1, 2 1, 3
1
1
0()
2,1 2,3
0
1
()
3,1 3,2
R j lp jM jM
p
c
Ip
V
p
jM R j l jM I
ss
c
s
I
t
jM jM R R j lp
lt
c
t
ωω ω
ω
ωω ω
ω
ωω ω
ω
+− − −
=− +− −
−−++−
(3)
Where, IP is current in the primary circuit, is
denotes the current in the secondary circuit, It is
current in the receiver circuit, and R1, R2, R3 indicate
internal circuit resistances.
Due to the symmetric state of the system, i.e. M1,
2=M2, 1, M1, 3=M3, 1, and M2, 3=M3,2) and by
replacing the self-impedance with Z factor, the
following equation is obtained:
1,2 1,3
1
0
2,1 2,3
0
3,1 3,2
ZjMjM
I
p
V
jM Z jM I
s
I
t
jM jM Z
t
ωω
ωω
ωω
−−
=− −
−−
(4)
By solving equation (4), the current of each
circuit of each circuit is computed as:
22
..
2,3
.
1
22 2 22 3
.M . . . . . 2 . .
1,3 2, 3 1, 2 1, 2 1,3 2,3
ZZ M
pt
IV
p
ZZMZZZMiMMM
pp ptt
ω
ωω ω
+
=
++++
(5)
22
(.. ) . .
1, 2 2, 3 1, 3
.
1
22 2 22 3
.M . . . . . 2 . .
1, 3 2, 3 1, 2 1, 2 1, 3 2, 3
iZ M M M
t
IV
s
ZZMZZZMiMMM
pp ptt
ωω
ωω ω
−
=
++++
(6)
2
i( . . ) . .
1, 3 1, 2 2,3
.
1
22 2 22 3
.M . . . . . 2 . .
1, 3 2 ,3 1, 2 1, 2 1, 3 2, 3
ZM MM
p
IV
t
ZZMZZZMiMMM
pp ptt
ωω
ωω ω
−
=
++++
(7)
By calculating the current of the each coil, the produced and
consumed powers are obtained,
2
.
2
RI
s
=
,
.I
11
PV
=−
,
2
.
3
RI
t
=
(8)
Where, P1 is t power produced by his source. By
replacing the current in the equation (8) and
calculating the power for each circuit, the efficiency
of the whole system is obtained:
33
2
.
21 1
PP
P
PP P
η
==
(9)
2
2
i( . . ) . .
1, 3 1, 2 2, 3
..
1
22 2 22 3
.M . . . . . 2 . .
1, 3 2, 3 1, 2 1, 2 1,3 2 ,3
22
(. . )
2,3
2
.
1
22 2 22 3
.M . . . . . 2 . .
1, 3 2, 3 1, 2 1, 2 1, 3 2 ,3
ZM MM
p
VR
L
ZZMZZZMiMMM
pp ptt
ZZ M
pt
V
ZZMZZZMiMMM
pp ptt
ωω
ωω ω
η
ω
ωω ω
−
++++
=
−+
++++
(10)
(
)
(
)
2
2
.i( .. ) . .
1, 3 1, 2 2 , 3
22 22 2 22 3
(. . ) .M .. . .. 2 . .
2,3 1,3 2,3 1,2 1,2 1,3 2,3
RZM MM
Lp
ZZ M Z Z M ZZZ M iM M M
pt p p pt t
ωω
η
ωωω ω
−+
=
+++++
(11)
At the resonant frequency, the capacitive and
inductive parts of the circuit eliminate and the circuit
is purely resistive. Hence, the maximum efficiency is:
max:
:
f
r
r
ZR
pp
at f Z R
ss
ZRR
ttL
η
=
=⎯⎯⎯⎯→
=+
(12)
() ()()
max
2
2
.i( .. ) . .
1, 3 1,2 2 , 3
22 22 2 22 3
(. . ) .M .. . .. 2 . .
2,3 1,3 2,3 1,2 1,2 1,3 2, 3
RRM MM
p
L
R RR M R R M R RR RR M iMM M
pt p p pt tLLL
ωω
η
ωω ω ω
−+
=
++ + + +++ +
(13)
2 EXPERIMENTAL RESULTS
These tests are carried out on three different types of
topologies in witricity and results also show a clear
relationship and the validity between the theory and
the formulas have been obtained before. We have also
carried out a comparative study between the three
types of series, parallel and topology modify without
the resonant ring which can be found in each test in
terms of power quality the results of each methods.
By doing experimental tests on these three different
topologies mentioned before, as shown in figure 3.
These three types of topologies have just used in the
transmitter side of experiment. However, the
topology of the receiver is fixed in all three tests also
20 cm distance between transmitter and receiver is
considered and resonant ring moves between the two
parts(transmitter and receiver) which is shown by the
symbol d1 which mentioned in figure 2 and the results
of this experiment are clearly shown in figure 6. For
a comprehensive view on the issue, a comparative test
have done, without the existence of the resonant ring
this means that we change the distance between
transmitter and receiver (D in figure (2), From the
results it can be concluded that shown in Figure 7. It
should also be noted that the load resistance of 50
ohms is considered.
AnalysisofRelayEffectonWirelessPowerTransfer
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