Using H(¯x, 0) = G( ¯x, 0) = 0, ∇
p
i
H
i
( ¯x, 0) = 0 and
∇
q
j
G
j
( ¯x, 0) = 0, (i = 1, 2, ..., k, j = 1, 2, ..., m), we
obtain (¯x, ¯v, ¯w,
¯
λ, ¯µ, ¯z, ¯p = 0, ¯q = 0) belongs to the
domain feasible for (MPD) and also the respective
values of the objectives are equivalent.
We now claim that for (MPD) ( ¯x, ¯v, ¯w,
¯
λ, ¯µ, ¯z, ¯p =
0, ¯q = 0) is efficient.
On the contrary, let us assume that
( ¯x, ¯v, ¯w,
¯
λ, ¯µ, ¯z, ¯p = 0, ¯q = 0) be efficient for (MPD),
therefore ∃ (u, v, w, λ, µ, z, p, q), which is in the feasible
domain for (MPD) such that
h
φ
1
(u)+ u
T
z
1
ψ
1
(u)− u
T
v
1
, ...,
φ
k
(u)+ u
T
z
k
ψ
k
(u)− u
T
v
k
i
−
h
φ
1
( ¯x) + ¯x
T
¯z
1
ψ
1
( ¯x) − ¯x
T
¯v
1
, ...,
φ
k
( ¯x) + ¯x
T
¯z
k
ψ
k
( ¯x) − ¯x
T
¯v
k
i
∈ K\{0}
which using (11) imply
h
φ
1
(u)+ u
T
z
1
ψ
1
(u)− u
T
v
1
, ...,
φ
k
(u)+ u
T
z
k
ψ
k
(u)− u
T
v
k
i
−
h
φ
1
( ¯x) + τ( ¯x|C
1
)
ψ
1
( ¯x) − τ( ¯x|D
1
)
, ...,
φ
k
( ¯x) + τ( ¯x|C
k
)
ψ
k
( ¯x) − τ( ¯x|D
k
)
i
∈ K\{0},
a contradiction to the Theorem 3.1. Therefore,
the required result.
4 CONCLUSIONS
In this paper, we have presented a current class of
higher order (K × Q)- F-type I function. A Mond-
Weir type higher order multiobjective fractional prob-
lem (which is also nondiifferentiable) over cone has
been constructed. Considering this dual program, we
have established the corresponding duality relation un-
der higher order (K × Q)- F-type I function. The re-
sults which we have put forward in this paper are ex-
tension of some previously studied results appearing in
the literature. It is to be noted that, researchers can
further extend our work for different types of duality
problems for fractional problems, such as, mixed type
duality etc.
ACKNOWLEDGEMENTS
The first author is grateful to the Ministry of Human
Resource and Development, India for financial support,
to carry out this work.
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