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Appendix
Proof Sketch of Theorem 1: The proof of Theorem
1 is based on the proof of Lemma 1 which concerns
the state-feedback control problem (for a detailed
proof see (Gershon and U. Shaked, 2010), (Gershon
and U. Shaked, 2005)). We first bring in Part I, a
proof sketch of Lemma 1 which is also needed for
the solution of the output-feedback control. We then
bring, in Part II, the derivation of the sufficiency part
of Theorem 1, which is derived from Lemma 1, and
the necessity part of the proof of Theorem 1.
Part I: The proof of Lemma 1 follows the standard
line of applying a Lyapunov-type quadratic function
in order to comply with the index of performance.
This is usually done by using two successive com-
pleting to squares operations however, since the
reference signal of r
k
is introduced in the dynamics
of (2a), we apply a third completing to squares
operation with the aid of the fictitious signal of θ
k+1
.
This latter signal finally affects the controller design
through it’s causal part [θ
k+1
]
+
(for a detailed proof
see (Gershon and U. Shaked, 2010), (Gershon and
U. Shaked, 2005)).
Part II: The sufficient part of the proof of Theorem 1
stems from the above proof of Lemma 1 where B
2,k
=
0, D
2,k
= 0. Analogously to the proof of Lemma 1,
we obtain the following: J
B
(r
k
,u
k
,w
k
,x
0
) =
−
N−1
∑
k=0
|| ˆw
k
− R
−1
k+1
B
T
1,k
˜
θ
k+1
||
2
R
k+1
−γ
2
||x
0
− (γ
2
R
−1
−
˜
Q
0
)
−1
˜
θ
0
||
2
R
−1
−γ
−2
˜
Q
0
.
where we replace θ
k+1
, Q
k
by
˜
θ
k+1
and
˜
Q
k
, respecti-
vely and where
˜
P
0
= [R
−1
−γ
−2
˜
Q
0
]
−1
, x
0
= γ
−2
˜
P
0
˜
θ
0
= [γ
2
R
−1
−
˜
Q
0
]
−1
˜
θ
0
The necessity follows from the fact that for r
k
≡ 0, one
gets
˜
J(r,ε) = 0 (noting that in this case
˜
θ
k
≡ 0 in (14)
and therefore the last 3 terms in
˜
J(r,ε) of Theorem
1 are set to zero) and J
B
< 0. Thus the existence of
˜
Q > 0 that solves (13) is the necessary condition in
the BRL.
H
∞
Measurement-feedback Tracking with Preview
331