1
(km)
≥80
2.2 Parameter Design of the Drive
Motor
Motor is the critical component for good power
performance of the extended range electric vehicle.
In the parameter matching process, the smallest
number of system parameters is used to meet the
dynamic requirements of the design index. The main
parameters such as the base speed n
0
, the maximum
speed n
max
, the rated power P
0
, the peak power P
max
and the peak torque N
max
need to be matched (Hu He,
2012). Prior to matching the parameters of the
driving motor, the parameters of the transmission
system have to be determined first. The motor has
the characteristic of delivering constant torque at
base speed and delivering constant power between
the base speed and the maximum speed (Dong
Xinyang, 2012), which makes it ideal to meet the
speed and torque requirements of the vehicle. As
shown in table 1, the speed ratio of the transmission
system is tentatively defined as 7.9.
2.2.1 The Base Speed n
0
and the Maximum
Speed n
max
The designed maximum speed of the drive motor
should meet the requirement as stated in this
formula:
0
max
max
377.0
ii
rn
V
g
In the formula, v
max
(km/h)
is the designed
maximum speed of the vehicle, r (m) is the tire
radius, i
g
i
0
is the total transmission ratio of the
transmission system (value of 7.9 is taken in this
paper). Values for each respective parameter are
shown in table 1 and table 2. These input values
yield results of n
max
≥ 9906r/min, and n
max
=
10000r/min.
The relationship between the maximum speed
n
max
and the base speed n
0
of the motor is defined as
below.
0
max
n
n
In the formula,
is the constant power expansion
coefficient. The greater its value, the greater the
output torque of the motor at low speed, and the
better the corresponding starting and climbing
performance of the vehicle. But it will increase the
size of the power converter if the value is too large.
The reasonable value is 2-4(Deng Chunrong, 2014).
Based on these values, 2500
≤
n
0
≤5000
is obtained.
In this paper,
is defined as 3.3, and the base speed
n
0
equals to 3300 r/min.
2.2.2 The Rated Power P
0
and the Peak
Power P
max
The power balance equation for the vehicle driving
is shown as below.
dt
du
muU
A
D
C
mgumgfu
e
P
aaa
2
15.21
sincos
3600
1
In the formula, P
e
(kW) is the drive motor power,
is the transmission efficiency, m (kg) is the vehicle
weight, g (m/s
2
) is the gravitational acceleration. is
the rolling resistance coefficient,
(°) is the slope
angle, C
D
is the air resistance coefficient, A(m
2
) is
the frontal area,
is the rotary mass conversion
coefficient, du/dt(m/s
2
) is the acceleration.
The motor demand power and the maximum
speed.
The relationship between the motor demand
power and the maximum speed must satisfy the
formula below (Yu Zhisheng, 2006).
3
maxmax
761403600
1
v
AC
v
mgf
P
D
u
The vehicle weight for the test is taken as,
m=m
0
+180kg (Wang Da, 2015). Using values from
table 1 and above vehicle weight produces P
1
=
22.3kW.
The motor demand power and the
acceleration time between 0 km/h to100km/h.
The motor power required to meet the
acceleration performance of the vehicle is stated as
below(Yu Zhisheng, 2006).
322
5
1
3
2
21000
1
fDafbf
a
a
AvCmgfvvv
t
m
P
In the formula,
is a constant with value of 1.06,
t
a
(s) is the acceleration time between 0 to 100 km/h.
v
f
(m/s) is the speed at the end of acceleration, which
equals to 12m/s.
a
is the air density, which equals
to 1.202Ns
2
m
-4
. The other parameters are same as
above. These input values yield P
2
= 74.33kW.